Question

p =8000 . R=5% per annum. n=3 years find the amount of 3 year. please answer ​

Answer 1

Answer:

Solution: Here, P = $ 8000, R = 5 % per annum and n = 3 years. = $ 9261. Thus, amount after 3 years = $ 9261.

Step-by-step explanation:

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Answer 2

★ Cᴏɴᴄᴇᴘᴛ :

According to the given information the principal is ₹8000, rate of Interest per year is 5% and time is 3 years. We need to find the amount at the end of the third year. So here this can be done by two methods. For the 1st method we need to apply a specific formula which is easier and shorter than the second method. For the second method we need to apply the basic formula for finding interest of each year adding with principal to get the amount at the end of each year

☞ 1sᴛ Mᴇᴛʜᴏᴅ :

Principal (P) = ₹8000, Rate (r) = 5%, Time (n) = 3 years

Using Formula

$\underline{\boxed{ \sf \green{ A }= \blue{P(1 + \frac{r}{100})^{n}}}}$

Putting all the required values according to the given data

$\hookrightarrow\sf A= \frak{ 8000(1 + \frac{5}{100})^{3}}$

Cancelling 5/100

$\hookrightarrow\sf A= \frak{8000(1 + \cancel \frac{5}{100})^{3}}$

$\hookrightarrow\sf A= \frak{ 8000(1 + \frac{1}{20})^{3}}$

$\hookrightarrow\sf A= \frak{8000( \frac{21}{20})^{3}}$

$\hookrightarrow\sf A= \frak{8000 \times \frac{9261}{8000}}$

$\hookrightarrow\sf A= \frak{ \cancel{8000} \times \frac{9261}{ \cancel{8000}} }$

$\quad \: \: \frak{ \green{A}= \blue{ 9261}}$

• Hence, the amount at the end of 3 years is ₹9261

_______________________________

☞ 2ɴᴅ Mᴇᴛʜᴏᴅ :

Principal (P) = ₹8000, Rate (R) = 5%, Time (T) = 3 years

Using Formula

$\star \: \: \underline{\boxed{\frak{ \red{Interest} = \purple{{\frac{ \sf{P \times R \times T}}{100}}}}}}$

For the first year we need to apply, again for the next year it's same and same case for the last year

1st Year

$\dashrightarrow \sf{Interest = \frac{ \sf{P \times R \times T}}{100}}$

For getting the amount at the end of the first year we need to put the required values in the formula

$\dashrightarrow \sf Interest = \frak{ \frac{8000 \times 5\times 1}{100}}$

$\dashrightarrow \sf Interest = \frak{80 \times 5}$

$\dashrightarrow \sf Interest = \frak{400}$

The Interest for the first year is ₹400

Pricipal is ₹8000

Amount = P + I

Amount at the end of the first year = 8000 + 1200 = ₹8400

2nd Year

Principal (P) = ₹8400, Rate (R) = 5%, Time (T) = 1 year

$\dashrightarrow \sf{Interest = \frac{ \sf{P \times R \times T}}{100}}$

For getting the amount at the end of the second year we need to put the required values in the formula

$\dashrightarrow \sf Interest = \frak{ \frac{8400 \times 5\times 1}{100}}$

$\dashrightarrow \sf Interest = \frak{84 \times 5}$

$\dashrightarrow \sf Interest = \frak{420}$

The Interest for the first year is ₹420

Pricipal is ₹8400

Amount = P + I

Amount at the end of the second year = 8400 + 420 = ₹8820

3rd Year

Principal (P) = ₹8000, Rate (R) = 5%, Time (T) = 1 year

$\dashrightarrow \sf{Interest = \frac{ \sf{P \times R \times T}}{100}}$

For getting the amount at the end of the third year we need to put the required values in the formula

$\dashrightarrow \sf Interest = \frak{ \frac{8820 \times 5\times 1}{100}}$

$\dashrightarrow \sf Interest = \frak{88.2\times 5}$

$\dashrightarrow \sf Interest = \frak{441}$

The Interest for the first year is ₹441

Pricipal is ₹8820

Amount = P + I

Amount at the end of the third year = 8820 + 441 = ₹9261

• Hence, the answer is ₹9261

[Note : It should be easier to apply the first process and execute it]