Question

P=9000 Rs R= 10 p.c.p.a N =2 year find compond interest​

Answer 1

Principal (P) = Rs. 9000

Rate (R) = 10 % p.a

no. of years (N) = 2 year

$\boxed{ \gray{\underline {\sf{ Compound \: interest = {P(1 + \frac{R}{100} )}^{N} }}}}$

$\sf = {9000(1 + \dfrac{10}{100}) }^{2} \\ \\ \sf \: = 9000 {( \dfrac{100 + 10}{100} )}^{2} \\ \\ \sf \: = 90{00} {( \frac{110}{1 00} )}^{2} \\ \\ \sf \: = 9 \cancel0 \cancel{00}( \frac{110 \times 11 \cancel0}{1 \cancel0 \cancel0 \times 1 \cancel{00}} ) \\ \\ \sf \: = 9 \times 11 \times 11 \: \: \: \: \: \: \: \: \boxed{ \purple{\implies \: Rs. \: 1089}}$