Question

P=9000 Rs R= 10 p.c.p.a N =2 year find compond interest full solutions​

Answer 1

Answer:

Interest for 1st year = P × R × T / 100

9000 × 10 × 1 /100

= ₹900

Amount at the end of first year = 9000 + 900 = 9900

Principle for second year = ₹9900

Interest for 2nd year = P × R × T / 100

9900 × 10 × 1 / 100

= ₹990

Amount at the end of second year = 9900 + 990

= ₹10,890

Compound interest = amount - original principle

10890 - 9000 = ₹1890

The compound interest is ₹1890

Answer 2

Principal (P) = Rs. 9000

Rate (R) = 10 % p.a

no. of years (N) = 2 year

$\boxed{ \gray{\underline {\sf{ Compound \: interest = {P(1 + \frac{R}{100} )}^{N} }}}}$

$\sf = {9000(1 + \dfrac{10}{100}) }^{2} \\ \\ \sf \: = 9000 {( \dfrac{100 + 10}{100} )}^{2} \\ \\ \sf \: = 90{00} {( \frac{110}{1 00} )}^{2} \\ \\ \sf \: = 9 \cancel0 \cancel{00}( \frac{110 \times 11 \cancel0}{1 \cancel0 \cancel0 \times 1 \cancel{00}} ) \\ \\ \sf \: = 9 \times 11 \times 11 \: \: \: \: \: \: \: \: \boxed{ \purple{\implies \: Rs. \: 1089}}$