Question

P(A)=0.99 p(A') =______

Answer 1

P(A)+ P(A')=1

0.99+P(A')=1

P(A')=1-0.99

P(A')=0.01

Answer 2

As per the data given in the above question.

We have to find the probability of event A which is not happening i.e. P(A') or P( not A)

Given,

$P(A)=0.99$

Step-by-step explanation:

Complementary Event:

It is defined as for any event A, the sum of the probability of its happening and the probability of its not happening, is 1 .

$P(A) + P(not A) = 1 \: \: \: \: ...(1)$

or

$P(A) + P(A') = 1$

Now ,

Rearrange the equation ,

$P(A') = 1 - P(A) \: \: \: \: \: \: ...(2)$

Put the value of P(A) then we get ,

$P(A') = 1 - 0.99$

Subtract the value ,we get

$P(A') = 0.01$

Hence,

$P(A') = 0.01$

Project code #SPJ3