Math, asked by kranthi2685, 10 months ago

P(A) = 1/4 p(B) = 1/2 P(A and B) = 1/8 find P( A or B) and P( not A and not B)

Answers

Answered by fasalniha20
0

Answer:

P(A or B)=5/8,P(notA and notB)=3/8

Step-by-step explanation:

We know that

P(A or B)=P(A union B)

P(A or B)=P(A)+P(B)-P(A and B)

=1/4+1/2-1/8

=5/8

P(not A and not B)=P(A or B)'

=1-P(A or B)

=1-5/8

=3/8

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