Question

P(a) = 1/6 , p(b) = 1/6 then probability of a intersection b ?

Answer 1

Answer:

Step-by-step explanation:

As most of the answers have pointed out, P (A and B) is necessarily 0 if A and B are mutually exclusive. Because the definition of “mutually exclusive” actually MEANS that the probability of P(A and B) is 0!!

However, I suspect the questioner really meant: What is the probability of A OR B if A and B are mutually exclusive?

If the events are mutually exclusive, then the probably of A OR B is:

P(A) + P(B) = 1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2.