Math, asked by sameerafasimha, 19 days ago

P=a^2+4b^2-6ab,Q=a^2-b^2+2ab and R=b^2+6.find p+2Q+2R

Answers

Answered by preeti353615
0

Answer:

If  P=a^2+4b^2-6ab, Q=a^2-b^2+2ab and R=b^2+6 then P+2Q+2R = 3 a^2 + 4b^2 -2ab + 12

Step-by-step explanation:

Given:

P=a^2+4b^2-6ab\\ Q=a^2-b^2+2ab

andR=b^2+6

Find : P+2Q+2R

Put the values of P,Q and R and then solve

P+2Q+2R = a^2+4b^2-6ab + 2 (a^2-b^2+2ab ) + 2 (b^2+6)\\=  a^2+4b^2-6ab + 2 a^2 -2b^2+4ab   + 2 b^2+12

Rearrange the similar terms

= a^2+ 2 a^2 +4b^2 -2b^2  + 2 b^2 -6ab+4ab  +12\\= (1 + 2) a^2 + (4 -2 +2)b^2 + (-6+4)ab + 12\\= 3 a^2 + 4b^2 -2ab + 12

Similar questions