Question

P(a+b,a-b) and Q(a-b,a+b) .Find its answer by the distance formula ( coordinate geometry)

Answer 1

this is Ur required result in attachment

Answer 2

$2\sqrt{2}b$ units.

Step-by-step explanation:

The distance between the two given points on the coordinate plane $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is given by the formula

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }$ .

Now, we are given two points P(a + b, a - b) and Q(a - b, a + b) and we have to find the distance between them.

So, the distance = $\sqrt{(a + b - a + b)^{2} + (a - b - a - b)^{2} }$

= $\sqrt{(2b)^{2} + (- 2b)^{2} }$

= $\sqrt{8b^{2} }$

= $2\sqrt{2}b$ units. (Answer)