Question

P(A)-P(Ā)=0.3 than P(A)​

Answer 1

Answer:

We know,

P(A)+P(Ā)=1...(1)

P(A)-P(Ā)=0.3...(2).... given

Add both equations, we get

2[P(A)]=1.3

P(A)=1.3/2

P(A)=0.65

Answer 2

Answer:

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Step-by-step explanation:

Given : Is A and B are two events such that P(A intersection B) = 0.2, P(A union B) = 0.8, P(Ā) = 0.4.

To find : P(B) ?

Solution :

P(Ā) = 0.4

P(A)=1-P(Ā)

P(A)=1-0.4

P(A)=0.6

We know that,

P(A\cup B)=P(A)+P(B)-P(A\cap B)P(A∪B)=P(A)+P(B)−P(A∩B)

0.8=0.6+P(B)-0.20.8=0.6+P(B)−0.2

0.8=0.4+P(B)0.8=0.4+P(B)

P(B)=0.8-0.4P(B)=0.8−0.4

P(B)=0.4P(B)=0.4

Therefore, the probability of B is P(B)=0.4.

#Learn more

If p(A intersection B)=0.3,p(A Bar intersection B)=0.45,then p(B)

HOPE IT HELPS