Math, asked by pratibha8949, 10 months ago

(p-a) (p-b) (p-c)......................(p-z)
Whatds thde foprobable answer?

Answers

Answered by qwchair
0

(p-a) (p-b) (p-c)......................(p-z)

  • This terms can also be written as (p-a) (p-b) (p-c).................(p-p).....(p-z), which includes the term (p-p) = 0.
  • From above we get, (p-a) (p-b) (p-c).................(0).....(p-z). Here, the term (p-p) is replaced as 0 (zero).
  • As we know, anything multiplied by 0 is 0. All the terms are multiplied with 0.

Thus, the answer is 0 (zero).

Answered by amitnrw
1

Given : (p-a) (p-b) (p-c)......................(p-z)

To find :    Probable answer (p-a) (p-b) (p-c)......................(p-z)

Solution:

(p-a) (p-b) (p-c)......................(p-z)

it looks like Question has variable

from a to z

p comes in between a to z

hence there will be one factor (p - p) as well

=> (p-a) (p-b) (p-c)......................(p-z)

= (p-a) (p-b) (p-c)..........(p - p).........(p-z)

= (p-a) (p-b) (p-c)..........(0).........(p-z)

Anything mutiplied with 0 will be 0

= 0

Hence Probable answer of (p-a) (p-b) (p-c)......................(p-z) = 0

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(x-a)(x-b)(x-c).........(x-z)?

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