P. A train leaves station A at 08:00 hours to reach station B
at 09:30 hours, travelling at 90 km/h. At 10:00 hours, it
leaves station B and travels at 110 km/h to reach station
Cat 12:00 hours. What was the average speed of the train
in travelling from station A to station C?
Answers
Answered by
7
- Average speed =total distance/total time
- total distance travelled =90*1.5 + 110*2=355km
- total time =4 hrs
- average speed=88.75km/hr
doubt12:
ok
no time taken is 1.5+2 hours. because is not running between 9:30 to 10:00
that is 3.5 hour
for average speed we simply count the time taken to travel between two position either the object is moving or not
u may right, but my think is that average speed of trains are labeled on the basis of running period. otherwise if a train is delayed for 1or 2days then it's average speed gets very low.
ya u r correct i also think so but we need to go through the formula
it would be better to have correct answer from the one who posted this question
please give correct answer who has posted it.
The correct answer is 88.75 km/h
okkk
Answered by
2
Answer:
Distance traveled between A and B
=90*3/2=135km
Distance traveled between B to C
=110*2=220km
Total distance traveled =220+135=355km
Tolal time taken=2+1.5=3.5h
Avg speed=total distance/time
=335/3.5=95.71km/h
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