(P+a/v^2)(V-b)=nRTfind dimensions of a and b where p is pressure and V is volume R is ideal gas constant v^2is velocity and T is temperature
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(p+a/v2)(V-b) =RT Pis pressure,V is volume and T is temperature[P]=[F/A]=[MLT-2/L2]=[ML-1/T-2][V]=[L3]We cannotadd or subtract quantities of different Dimensions Therefore[ P ]=[a/V2]=[a]= [PV2]=[ML-1T-2L6] =[ML5T-2] Therefore [a]=[ML5T-2] similarly, [B] =[V]=[L3]
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