Question

p alone can complete a work in 10 days and q alone can complete the same work in 20 days if p and q work together then in how many days the same work will be completed​

Answer 1

p and q can complete the work in 6 2/3 days

Given:

p alone can complete a work in 10 days

q alone can complete the same work in 20 days

To find:

If p and q work together then in how many days the same work will be completed​

Solution:

p alone can complete a work in 10 days

⇒ Then the work can be done by p in 1 day = 1/10

q alone can complete a work in 20 days

⇒  Then the work can be done by q in 1 day = 1/20  

If they both started working together

The work can be done in one day

= $\frac{1}{10} +\frac{1}{20}$  = $\frac{2 + 1}{20}$ = $\frac{3}{20}$  

p and q can do $\frac{3}{20}$ work in 1 day

The number of days to complete 1 work = $\frac{1}{\frac{3}{20} } (1)$ = $\frac{20}{3}$ = 6 2/3 days

p and q can complete the work in 6 2/3 days

#SPJ2

Answer 2

Answer:

The answer to the given question is that p and q can complete the work in

$6 \times \frac{2}{3} days$

Step-by-step explanation:

Given :

p alone can complete a work in 10 days.

q alone can complete the same work in 20 days.

To find :

How many days the same work will be completed if p and q work together?

Solution :

p alone can complete a work in 10 days.

The work can be done by p in 1 day is

$\frac{1}{10}$

q alone can complete a work in 20 days.

The work that can be completed by q in one day is

$\frac{1 }{20}$

The work done by both of them, if they start working together means

$\frac{1}{10} + \frac{1}{20} = \frac{2 + 1}{20} = \frac{3}{20}$

The work done by both of them in one day is

$\frac{3}{20}$

The days required to complete 1 work is

$\frac{1}{ \frac{3}{20} }(1) = \frac{20}{3}$

On division, we get the value as

$6 \times \frac{2}{3} days$

Therefore, the p and q can complete one work in

$6 \times \frac{2}{3} days$

# spj5

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