Question

P & Q are the solution of the equation
x² +11x+28 find the equation for which the solution is P+2 & Q+2 .​

Answer 1

Answer:

$x^{2} -7x+10=0$

Step-by-step explanation:

So P+Q=-11,PQ=28

Let A=P+2,B=Q+2

so A+B=-7,AB=10

$=(A)(B)\\=(P+2)(Q+2)\\=P(Q+2)+2(Q+2)\\=PQ+2P+2Q+4\\=PQ+2(P+Q)+4\\=28+2(-11)+4\\=10$

So Equation Is :$x^{2} -7x+10=0$