Question

P& Vertical 2. In the given figure, ABCD is a rectangle whose diagonals AC and BD intersect at O. If ZOAB = 32°, find (i) ZACB (ii) ZOBC B​

Answer 1

Answer:

angle obc =90-28=62

as the sum of the angles are complementary.

Step-by-step explanation:

BAD = 90° ( ABCD is a rectangle)

<CAD = <BAD-28

= 90 - 28

= 62°

<CAD = 62°

Now,

In Triangle CAD and DBC

<ADC = <BCD (each 90°)

AD = BC (Opposite sides of rectangle)

CD =DC (common)

So, Triangle CAD congurent Triangle DBC

(By S. A. S criteria)

<DBC = <CAD (C. P. C. T)

< DBC = 62°

<OBC = 62