p and F are respectively the midpoints The of the equal side ab and ac of angle abc see figure then
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Given E and F are mid point of equal sides AB and AC of triangle ABC
In ΔABF and ΔACE
AB=AC (given )
∠A=∠A (common angle )
AF=AE (halves of equal sides)
∴ΔABF≅ΔACE (SAS rule)
∴BF=CF (CPCT)
This is an example the answer
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