Question

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. show that ar(APB) =ar(BQC) ​

Answer 1

Hey Mate ..

Step-by-step explanation:

Since APB and ||gm ABCD are on the same base AB and between the same parallels AB and DC

ar(APB) = ....(i)

Similarly ar(BQC) = ...(ii)

From (i) and (ii) we have

ar(APB) = ar(BQC)

Hope this helps you...