P and Q are any two points lying on the sides DC and AD respectively of a parallelogram
ABCD. Show that ar (APB) =ar (BOC).
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P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. ... Given: P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. To Prove: ar(ΔAPB) = ar(ΔBQC). Proof: ∵ ΔAPB and || gm ABCD are on the same base AB and between the same parallels AB and DC.
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