Question

P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar(APB) =ar(BQC)

Answer 1

Step-by-step explanation:

Use this statement ,'Area of triangle between two parallel lines is half the area  of the parallelogram.'                                                            ^

Therefore area of triangle APB = 1/2 area of ABCD            |

Therefore area of triangle BQC = 1/2 area of ABCD. Same statement

Thus area of triangle abp = bqc.