Question

P and Q are centres of two circles of radii 12 and 3cm respectively. a and B are points of contact of common tangent xy. find a b​

Answer 1

Answer:

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Answer 2

Answer:

2 circle ⭕

1 radii =12cm 2 radii =3cm

common tangent = xy

Answer___

1. PO = 12-3=9 cm
2. QO= 12+3=15 cm

in ∆POQ

PO=QO+PQ

PO=9 CM

QO=15CM

( 15 )2 = (PQ) 2 +( 9) 2

(PQ) 2= (15 )2 - (9)2

(PQ) 2= 225 - 81

(Pq)2= 144

(PQ)=√ 144

(PQ)=12

ANSWER =12