Question

P and Q are points of trisection of a line segment joining points A (-4,3) and B (8,-15) , Q is nearest to B find the co ordinates of Q

Answer 1

Step-by-step explanation:

Since P and Q be the points of trisection of the line segment joining the points A(2,−2) and B(−7,4) such that P is nearer to A.

Therefore, P divides line segment in the ratio 1:2 and Q divides in 2:1 as shown in the figure.

Using section formula,

Coordinates of P = [

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

]

= [

1+2

1(−7)+2(2)

,

1+2

1(4)+2(−2)

]

= [

3

−3

,

3

0

]

= [−1,0]

Coordinates of Q =[

2+1

2(−7)+1(2)

,

2+1

2(4)−1(−2)

]

= [

3

−12

,

3

6

]

= [−4,2]

solution

Answer 2

Step-by-step explanation:

anwer is (4,-9)

hope it's help you ✌️