Question

P and Q are points of trisection of the diagonal BD of a parallelogram
ABCD. Prove that CQ ll AP.​

Answer 1

Answer:

ABCD is a parallelogram . AB is divided at P and CD at Q so that AP : PB = 3 : 2 and CQ : QD = 4 : 1 . If PQ meets AC at R then prove that AR = 73AC .