Question

P and Q are points on a circle with Centre O. R is a point on the circle such that OR bisects angle POQ. prove that R is the midpoint of PQ​

Answer 1

Step-by-step explanation:

IN TRIANGLE POR AND TRIANGLE QOR:

PO=OQ(Rdii)

RO=RO(Common)

ANGLE POR = ANGLE QOR(OR BISECTS ANGLE POQ)

THEREFORE TRIANGLE POR IS CONGURENT TO TRIANGLE QOR (SAS)

THEREFORE PR = QR(CPCT)

THEREFORE R IS THE MID POINT OF PQ.

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