p and Q are points on sides AB
and AC respectively of triangle ABC. If AP=3 cm, PB = 6 cm.
5cm and QC=10cm.Show that BC =3PQ
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Step-by-step explanation:
Given, AP = 3 cm and PB = 6 cm => AB = 9 cm
AP /AB = 1/3
Also, given AQ = 5 cm and QC = 10 cm
=>AC = 15 cm
AQ / AC = 1 / 3
∆APQ ~ ∆ABC. (BY SAS similarity criterion)
AP/AB=PQ/BC=AQ/AC
=> PQ/BC=1/3
=> 3PQ = BC
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