P and Q are points on the sides AB and AC respectively of a triangle ABC. PQ is parallel to BC
and divides the triangle ABC into 2 parts, equal in area. The ratio of PA:AB =______
Answers
Answer:
Area of ∆APQ=∆PBCQ
As it divides the triangle into equal parts
Now we know,PQ||BC it means ∆APQ~∆ABC
So, Area of ∆APQ/ Area of∆ABC=1/2(As,it divides the triangle into 2 equal parts)
(PA)²/(AB)²=1/2
PA/AB=1/√2
Answer is 1/√2
Given : P and Q are points on the sides AB and AC respectively of a triangle ABC.
PQ is parallel to BC and divides the triangle ABC into 2 parts, equal in area.
To Find : The ratio of PA: AB
Solution:
PQ || BC
∠P = ∠B Corresponding angles
∠Q = ∠C Corresponding angles
=> ΔAPQ ~ ΔABC AA similarity
Ratio of area of similar triangles = ( ratio of corresponding sides)²
Assume area of ΔABC = 2k sq units
Then Area of ΔAPQ = 2k/2 = k sq units
Area of Δ APQ / Area of ΔABC = (PA / AB) ²
=> k /2k = (PA / AB) ²
=> 1/2 = (PA / AB) ²
=> 1/√2 = PA/AB
=> PA : AB = 1 : √2
The ratio of PA: AB= 1 : √2
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