Math, asked by sindhusharavuri, 1 year ago

p and q are respectively midpoints of side ab and bc of a triangle abc and R is a midpoint of ap show that
1. area of triangle prq = 1\2area of arc
2. area of triangle rqc= 3\8 area of ABC
3. area of triangle pbq = area of arc

Answers

Answered by robin9388
5
(i) area (ΔPRQ)=1/2 area(APQ)[since RQ is a median and median divides triangle into equal areas]

=area(ΔABC)=............(1)

area (ΔARC)=1/2 area(ΔAPC) [in the ΔACP , CR is the median]

=1/2*1/2 area(ΔABC) [since CP is the median of ABC]

=1/4*x=x/4 ............(2)

from (1) and (2) area(ΔPRQ)=1/2 area(ΔARC)

(ii)

area(ΔRQC)=1/2 area(ΔARC) [since RQ is the median of triangle ARC]

=1/2*1/2area(ΔAPC)=1/4*1/2 area(ΔABC)=1/8x

(iii)

area(ΔPBQ)=area(ΔPQC)[the triangle with same base and between same set of parallel lines ]

=1/2 area(ΔAPC) [since PQ is the median of triangle APC]

=1/2*1/2 area(ΔABC)

=1/4 area(ΔABC)=x/4

from (2) area (ΔARC)=x/4

hence area(ΔPBQ)=area(ΔARC)

robin9388: Hehe sorry for making u confuse
robin9388: nope not same base
robin9388: no don't thank it's cool
robin9388: base are same but they are areas won't be equal
Answered by Anonymous
1

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