Question

P and Q are the mid-points of the side AB and BC respectively of the triangle ABC, right angled
at B. Then
(A) AQ? + CP2 = AC2
(B) AQ2 + CP2 = (4/5) AC2
(C) AQ2 + CP2= (4/3) AC2
(D) AQ2 + CP2 = (54) AC2






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Answer 1

Step-by-step explanation:

AQ

2

=AB

2

+BQ

2

=AB

2

+(

2

BC

)

2

=AB

2

+

4

BC

2

...(i)

Similarly CP

2

=BC

2

+BP

2

=BC

2

+(

2

AB

)

2

=

4

AB

2

+BC

2

...(ii)

∴AQ

2

+CP

2

=AB

2

(1+

4

1

)+BC

2

(1+

4

1

)

=

4

5

(AB

2

+BC

2

)=

4

5

AC

2

solution

Answer 2

Answer:

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