P and Q are the mid-points of the side AB and BC respectively of the triangle ABC, right angled
at B. Then
(A) AQ? + CP2 = AC2
(B) AQ2 + CP2 = (4/5) AC2
(C) AQ2 + CP2= (4/3) AC2
(D) AQ2 + CP2 = (54) AC2
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Answers
Answered by
1
Step-by-step explanation:
AQ
2
=AB
2
+BQ
2
=AB
2
+(
2
BC
)
2
=AB
2
+
4
BC
2
...(i)
Similarly CP
2
=BC
2
+BP
2
=BC
2
+(
2
AB
)
2
=
4
AB
2
+BC
2
...(ii)
∴AQ
2
+CP
2
=AB
2
(1+
4
1
)+BC
2
(1+
4
1
)
=
4
5
(AB
2
+BC
2
)=
4
5
AC
2
solution
Answered by
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