p and q are the points of trisection of the diognals bd of a parallelogram ABCD. prove that cq is parallel to ap
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We know that, diagonals of a parallelogram bisect each other.
⇒ OA=OC and OB=OD
Since P and Q are point of trisection of BD
∴ BP=PQ=QD
Now, OB=OD and BP=QD
⇒ OB−BP=OD−QD
⇒ OP=OQ
In quadrilateral APCQ, we have
OA=OC and OP=OQ
Diagonals of quadrilateral APCQ bisect each
∴ APCQ is a parallelogram.
⇒ AP∥CQ [ Opposite sides are parallel in parallelogram ]
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