Math, asked by gauravk7up, 7 months ago

P and Q are the points on side CA and CB respectively of ∆ABC , right angled at C .

Prove that : AQ2

+ BP2

= AB2

+ PQ2 ​

Answers

Answered by SanHolo2050
0

Answer:

man write the question properly

Answered by aaditya1234567890
6

Step-by-step explanation:

AB² = AC² + BC²

PB² = PC² + BC²

PQ² = PC² + CQ²

AQ² = CQ² + AC²

AQ² + BP² = CQ² + AC² + PC² + BC²

AB² + PQ² = PC² + CQ² + AC² + BC²

Therefore,

AQ² + BP² = AB² + PQ²

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