P and Q are the points on side CA and CB respectively of ∆ABC , right angled at C .
Prove that : AQ2
+ BP2
= AB2
+ PQ2
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0
Answer:
man write the question properly
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Step-by-step explanation:
AB² = AC² + BC²
PB² = PC² + BC²
PQ² = PC² + CQ²
AQ² = CQ² + AC²
AQ² + BP² = CQ² + AC² + PC² + BC²
AB² + PQ² = PC² + CQ² + AC² + BC²
Therefore,
AQ² + BP² = AB² + PQ²
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