P and Q are the points on the line segment joining the points A(8, 3) and B(11, 15) such that
AP=PQ=QB. Find the coordinates of P and Q
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let P(x, y) and Q (r, t )
a/c to question,
AP = PQ = QB
A ========P ========Q===========B
use section formula,
P divide the AB in 1 :2 ratio
x -co-ordinate of P
x =(1×11+2×8)/(3) =27/3 = 9
y-co-ordinate of P
y =(1×15+2×3)/(3) = 21/3 = 7
hence, point P = (9,7)
now, in the same way for Q
Q divide line AB in 2 : 1 ratio ,
x-co-ordinate of Q
x =(2×11+1×8)/3 =30/3 = 10
y -co-ordinate of Q
y=(2×15+3)/3 =33/3 = 11
hence, point Q =(10,11)
a/c to question,
AP = PQ = QB
A ========P ========Q===========B
use section formula,
P divide the AB in 1 :2 ratio
x -co-ordinate of P
x =(1×11+2×8)/(3) =27/3 = 9
y-co-ordinate of P
y =(1×15+2×3)/(3) = 21/3 = 7
hence, point P = (9,7)
now, in the same way for Q
Q divide line AB in 2 : 1 ratio ,
x-co-ordinate of Q
x =(2×11+1×8)/3 =30/3 = 10
y -co-ordinate of Q
y=(2×15+3)/3 =33/3 = 11
hence, point Q =(10,11)
abhi178:
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