Question

P and Q are the points on the sides DE and DF of a triangle DEF such that DP=5cm, DE=15cm, DQ=6cm, QF=18cm. Is PQllEF? Give reasons for your answer

Answer 1

Answer:

No, PQ is not parallel to EF.

Step-by-step explanation:

We are given P and Q are the points on the sides DE and DF of a triangle DEF such that DP=5cm, DE=15cm, DQ=6cm and QF=18cm.

Now, using the similarity condition we can prove that whether PQ is parallel to EF or not.

Therefore, $\frac{DP}{PE}=\frac{DP}{DE-PD}=\frac{5}{15-5}=\frac{5}{10}=\frac{1}{2}$.

Also, $\frac{DQ}{QF}=\frac{6}{18}=\frac{1}{3}$

Since, $\frac{DP}{PE}{\neq}\frac{DQ}{QF}$,therefore PQ is not parallel to EF.

Answer 2

Answer:

the picture is the answer