p and q are the points with co-ordinates (2,-1),and ('3,4).Find the co-ordinates of the points R ,such that PR is 2/5 of PQ
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Let R be (x,y)
P(2,-1)=(x1,y1)
Q(3,4)=x2,y2)
∵m:n=2:5
∴x=(m×x2)+(n×x1)÷(m+n)
=(2×3+5×2)÷7
=16/7=2 2/7
and,y=(m×y2+n×y1)÷(m+n)
=(2×4+5× -1)÷7
=3/7
∴R=(16/7,3/7) [Ans]
P(2,-1)=(x1,y1)
Q(3,4)=x2,y2)
∵m:n=2:5
∴x=(m×x2)+(n×x1)÷(m+n)
=(2×3+5×2)÷7
=16/7=2 2/7
and,y=(m×y2+n×y1)÷(m+n)
=(2×4+5× -1)÷7
=3/7
∴R=(16/7,3/7) [Ans]
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