Question

p and q are the points with coordinates (2,-1) and -3,4 find the coordinates of point r such that PR:RQ is 2:3

Answer 1

Answer:

by section formmula

Step-by-step explanation:

x=mx1+nx2/m+n

m:n=PR:RQ=2:3

(2,-1)and(-3,4)are coordinates

X1=2andX2=-3

so, X=2×2+3×(-3)/2+3

= 4-9/5

= -5/5=-1

y=my1+my2/m+n

y1=-1and y2=4

y=2×(-1)+3×4/2+3

= -2+12/5=10/5=2

coordinates of point= (-1,2)