Question

p and q are two points on equal sides AB and A C of an isosceles triangle ABC such that AP=AQ. Prove that BQ=CP

Answer 1

hey
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AB=BC ....(1)

AP=AQ......(2)

subtracting eqn 1 from 2

AB-AP=BC-AQ

BP=QC ..........(3)

in ∆BQC and ∆CBP

BP=QC( from (3) )
<C=<C (common angle)
BC=BC (common side)

∆BQC congruent ∆CBP by SAS criteria

hope helped
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