P and Q are two points on equal sides AB and AC of an isosceles Triangle ABC such that AP=AQ.Prove that BQ=CP.
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Answered by
68
if PBand QC are equal acc. to your diagram
so in tri. BQC and tri. CPB
PB=QC
ang. B=ang.C(angles opp. to equal side is equal)
BC=CB(comman)
tri BQCcong.to triangle CPB
therefore,BQ =QC (cpct)
so in tri. BQC and tri. CPB
PB=QC
ang. B=ang.C(angles opp. to equal side is equal)
BC=CB(comman)
tri BQCcong.to triangle CPB
therefore,BQ =QC (cpct)
Answered by
19
Answer:
If PB and QC are equal acc. to your diagram
so, in ∆BQC and ∆CPB
PB=QC
angle B = angle C
BC=CB
∆BQC is congurnt to ∆CPB
therefore, BQ = QC (cpct)
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