Question

P and Q are two points on equal sides AB and AC of an isosceles Triangle ABC such that AP=AQ.Prove that BQ=CP.

Answer 1

if PBand QC are equal acc. to your diagram
so in tri. BQC and tri. CPB
PB=QC
ang. B=ang.C(angles opp. to equal side is equal)
BC=CB(comman)
tri BQCcong.to triangle CPB
therefore,BQ =QC (cpct)

Answer 2

Answer:

If PB and QC are equal acc. to your diagram

so, in ∆BQC and ∆CPB

PB=QC

angle B = angle C

BC=CB

∆BQC is congurnt to ∆CPB

therefore, BQ = QC (cpct)