Question

p and q are two positive numbers such that p^q=q^p and q=9p. then the value of p is?

Answer 1

${9}^{9 \div 8}$

Answer 2

Answer:

$\sqrt[8]{9}$

Step-by-step explanation:

$p^q = q^p\\p = q^\frac{p}{q} \\p = (9p)^\frac{p}{9p} \\p = (9p)^\frac{1}{9}\\p^9 = 9p\\p^8 = 9\\p = 9^\frac{1}{8}$