p and q are two postive integers such that pq = 64. which of the following cannot be the value of p +q? 1)16 2)20 3)35 4)65
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2
The answer is 2)20.
The proof is here,
w.k.t
pq=64; so [ p=64/q]
therefore
64/q+q=20
[64+q²]/q=20
[64+q²]=20q
so,
q²-20q+64=0
q=16,4.
16 is not possible (I worked and got no answer)
so we can take 4.
(64/4)+4²=20
16+16=32.
This is also not possible.
so the answer is option 2.
Thank you!!
The proof is here,
w.k.t
pq=64; so [ p=64/q]
therefore
64/q+q=20
[64+q²]/q=20
[64+q²]=20q
so,
q²-20q+64=0
q=16,4.
16 is not possible (I worked and got no answer)
so we can take 4.
(64/4)+4²=20
16+16=32.
This is also not possible.
so the answer is option 2.
Thank you!!
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tej31:
but answer is give 35
Answered by
1
Answer: () 35
Step-by-step explanation:
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