Question

P and q are two stations. A train goes from p to q at 64 km/hr and returns to p at a slower speed. If its average speed for the whole journey is 56 km/hr.At what speed did it return?

Answer 1

Answer:

The return speed of the train is 48 km per hour

Explanation:

Let S be the average speed for the whole journey

Let S1 be the speed of the onward journey (p to q)

Let S2 be the speed of the return journey (q to p)

Clearly, S = (S1 + S2)/2

Given:

S = 56 km per hour

S1 = 64 km per hour

S2 = ?

Substituting the values, we get:

56 = (64 + S2)/2

112 = 64 + S2

S2 = 112 - 64

S2 = 48

Speed of train on return journey = 48 km per hour

Answer 2

Answer:

The return speed of the train is 48 km per hour

Explanation:

Let S be the average speed for the whole journey

Let S1 be the speed of the onward journey (p to q)

Let S2 be the speed of the return journey (q to p)

Clearly, S = (S1 + S2)/2

Given:

S = 56 km per hour

S1 = 64 km per hour

S2 = ?

Substituting the values, we get:

56 = (64 + S2)/2

112 = 64 + S2

S2 = 112 - 64

S2 = 48

Speed of train on return journey = 48 km per hour

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