Question

P and Q can do a piece of work in 8 days which P alone can do in 12 days.In how many days Q can do the same work.

Answer 1

Here's your answer!!

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(P+Q) can do a piece of work in 8 days.


(P+Q)'s one day work =
$= > \frac{1}{8}$


P can alone complete it in 12 days.


One day work of P =
$= > \frac{1}{12}$


Let the one day work of Q be =
$= > \frac{1}{x}$

A/q

=>(P+Q)'s = 1/8

$= > \frac{1}{12} + x = \frac{1}{8}$

$= > x = \frac{1}{8} - \frac{1}{12}$


$= > x = \frac{3 - 2}{24}$


$= > \frac{1}{24}$


Hence,

One day work of Q =
$= > \frac{1}{24}$


And he alone can complete it in 24 days.

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Hope it helps you!! :)

Answer 2

✹ Answer:

   24 days

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✹ Step-by-step explanation:

 

  Time taken by P and Q together

  to complete that work = 8

========================

One day's work of P and Q

together = 1/8

==========================

The time taken by P alone to

complete that work = 12 days

========================

One day's work of P

alone = 1/12

==========================

∴ One day's work of Q alone

= One day's of work P and Q  - One day's work of P alone

$=\dfrac{1}{8}-\dfrac{1}{12}\\\\\\=\dfrac{3-2}{24}\\\\\\=\dfrac{1}{24}$

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✹ So, Q can finish the work in

   24 days.