P and q do a piece of work in 30 days while q and r do the same work in 24 days and r and p can do it in 20 days.They all work together for 10 days.When q and r leave ,how many more days will p take to finish the work?
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Answer:
18 days
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Step-by-step explanation:
1/p + 1/q = 1/30
1/q +1/r = 1/24
1/r + 1/p = 1/20
adding all and dividing by two we get
1/p + 1/q + 1/r = (1/2).(1/30 1/24 + 1/20)
(1/2)(1/120)(4+5+6)
= 1/16
all together can complete work in 16 days
1/p = (1/p + 1/q + 1/r) - (1/q + 1/r)
1/p = 1/16 - 1/24
1/p = (1/48).(3-2)
so p = 48
p needs 48 days to complete work
let say work = w
16 days together required for w
in 10 days work done = 10w/16
remaining work = w- 10w/16
= 6w/16
w work done by p in 48 days
6w/16 work done by p in
(48/w)*(6w/16)
= 18 days
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