Math, asked by hcpant9120, 2 months ago

P and Q finished a work together in 90 days while P is twice efficient as Q then in how many days Q will finish the work alone

Answers

Answered by ItzSketch
12

\huge\fcolorbox{black}{red}{AnsweR:}

18 days.

Step-by-step explanation:

Together they complete the work in 12 days ,

So, in one day they complete 1/12work.

Since P is twice good as Q,

So P's work done in one day= 2x ,

& Qs work done in one day= x ,

So, 2x + x = 1/12,

3x = 1/12,

X = 1/36,

So, Qs work done in oneday= 1/36,

& P's work done in one day= 1/18,

So, P alone will take 18 days to complete a piece of work ,

\begin{gathered}{ \colorbox{lightgreen}{\huge{\textbf{\textsf{{\color{red}{@}}{\red{❣}}{|}}}} \huge{\textbf{\textsf{{\color{navy}{IT}}{\purple {Z}}{\pink{ \: SKETCH}}{\color{pink}{}}}}}}} \\ { \colorbox{yellow}{\huge{\textbf{\textsf{{\color{red}{}}{\red{}}{}}}} \huge{\textbf{\textsf{{\color{navy}{}}{\purple {}} \: \: \: \: {\pink{}} \: \: \: \: {\color{pink}{}}}}}}}\end{gathered}

Answered by Congofo1kItzSketch
1

Answer:

So, P alone will take 18 days to complete a piece of work ,

Similar questions