Question

P and Q have the co- ordinates (7,-4) and(-3,-4) and Q is the image of P. Find the equation of the mediator​

Answer 1

Answer: x = 2

Step-by-step explanation:

Midpoint of PQ = (2,-4)

Slope of PQ = 0

Slope of that line is = -1/0

Equation of that line is x = 2

Answer 2

Therefore the equation of the mediator is

x-2=0

Step-by-step explanation:

Given P and Q  have co-ordinate (7,-4)  and (-3,-4) and Q is the image of P.

The midpoint of P and Q is =$(\frac{7-3}{2} ,\frac{-4+4}{0} )$ =(2,0)

The equation of line passes through the point(2,0) is $\frac{-1}{0}$

(y-0)= m(x-2)

⇔y = m(x-2)

The slope of line passes through the point P(7,-4) and Q(-3,-4) is

$=\frac{-4+4}{-3-7} =0$

Therefore the slope of line perpendicular to PQ line is (m)=$\frac{-1}{0}$

Therefore the equation of line is

y =$\frac{-1}{0}$(x-2)         [since this line perpendicular to PQ line]

⇔x-2=0