Question

'P' and 'Q' horizontally push in the same
direction a 1200 kg crate. 'P' pushes with a
force of 500 newton and 'Q' pushes with a force
of 300 newton. If a frictional force provides
200 newton of resistance, what is the
acceleration of the crate?​

Answer 1

Answer:

0.5 m/s^2

Explanation:

As net force on crate = 500 + 300 -200

net force on crate = 600 N

Now,

Acceleration = Force /mass = 0.5 m/s^2

Answer 2

Answer:

Explanation:Fp =500N

Fq=300N

F=200N

Fnet= Fp+Fq-F

Fnet =600N

F=ma

Acceleration =Force/Mass

600/1200=0.5

Acceleration =0.5 m/s square