Math, asked by Ambikrajawat6281, 11 months ago

P and q take part in 100 m race .P runs at 6kmph. P gives q a start of 8 m and still beats him by 8 seconds. The speed of q is

Answers

Answered by Govindthapak
3

Step-by-step explanation:

total distance = 100 m

speed of P = 6 KMPH

= 6×5/18

= 5/3 m/s

time taken by P

= 100/5/3

= 100×3/5

= 60 sec

start given to Q is of 8m then the distance will be

100-8=92m

this 92m is covered in 68sec then the speed of Q will be

= 92/68 m/s

= 23/17 m/s

Answered by amitnrw
10

Answer:

4.87 km/hr

Step-by-step explanation:

p runs at 6 km/hr

= 6 * 1000/3600 m/s

= 5/3 m/s

time taken to complete 100 m

= 100/(5/3)

= 60 sec

let say speed of q = q m/s

distance covered by q in 60+8 sec =100-8 m

68q = 92

17q =23

q = 23/17 m/s

or 23 * 3600 /17*1000 km/hr

= 23*18/85 km/hr

= 4.87 km/hr

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