Question

P and Q when coming from their homes towards each other meet at a point X daily at 5:pm.speed of Pand Q is 40km/h and 30km/h respectively,one day Q got late therefore thay met at 5:30pm,find by how long Q got late (in minutes) if thay met at point X​

Answer 1

Answer:

30 minutes is answer of this question

Answer 2

Q got late by $70$ Min.

Explanation:

P can cover distance between 5 PM and 5:30 PM  

$= 40\times \frac{1}{2} = 20$  Km.

This distance must be covered by Q.

So, Q will take time $\frac{20}{30} = 40$ minutes.

Q will reach at point X after $(30+40) = 70$ Min.

Hence, Q got late by $70$ Min.