Question

P and R are point on CD of parallelogram ABCD show that ar(PAB) =ar(RAB) ​

Answer 1

∆(PAB) and ∆(RAB) have same base AB.............【1】

height of ∆(PAB) and height of ∆(RAB) are same because both are under same parallel lines....【2】

that is why ar(PAB) =ar(RAB)