Question

P and V of gas are related by law P=aV^2, where a=2N/m^2. The gas expands from volume 100 to 250L how much work is done by the gas during expansion?

Answer 1

Answer:

I think it will help u

Explanation:

When a gas expands at constant pressure then for a small change in volume 'dv' workdone is dw=pdv.

If the volume changes from 'v1' to 'v2' at constant pressure 'p', the work done is dw=p(v2−v1).

When work is done by the system against external pressure then dw=pdv

⇒w=∫v2v1pdv

So, by calculating with given numericals we get,

⇒dw=1.29atm(17.2L−12.5L)=1.29atm×(4.7L)=6.063atm.L.

To have the answer in terms of we use below units:

1atm=101325Pa

But1Pa=1J/m3 (because J=Pa.m3).

Substitute '