Question

P by q form of 1.324 bar on 324

Answer 1

let x=1.324324324.......... 1st

then 3gigits are repeating so then its periodicity is 1000.

1000x=1324.324324..... 2nd

subtract 2nd - 1st

1000x= 1324.324324

x= 1.324324

total =1323.00

999x = 1323

x= 1323/999