Question

P. Calculate the mass of potassium
chlorate required to liberate 6.72 dm² of
oxygen at STP. Molar mass of KCIO, is
122.5 g mol-'.​

Answer 1

Answer:

correct answer

Potassium chlorate decomposes, on strong heating, to form potassium chloride and oxygen. This decomposition of potassium chlorate can be achieved at lower temperatures when the catalyst manganese (IV) oxide is used. Therefore you need 73.5 g of potassium chlorate to liberate 6.72 dm³ of oxygen.

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