Math, asked by prishakapoor1161, 1 year ago

p can do a piece of work in 20 days. q is 25 percent more efficient than p. in how many days half the work is completed when both are working simultaneously?

Answers

Answered by imhkp4u
10

Question: P can do a piece of work in 20 days. q is 25 percent more efficient than p. in how many days half the work is completed when both are working simultaneously?



Solution: P can do a piece of work in 20 days. i.e. 20 days - 1 work.

In 1 day - 1/20 part of the work.

Q is 25 percent more efficient than P. i.e. Q will take 20 - 25% of 20 days = 15 days.

In 1 day - 1/15 part of the work.

In 2 days the combined work = 1/20 + 1/15 part of the work.

or, 7/60 part of the work.

Therefore, to complete full work, no of days = 120/7 days

Therefore, to complete half the work, no of days = 60/7 days [Ans]

Answered by seemasssingh4p893y4
0

Answer:

125:100=20/x

x=16

16 days is the right answer.

I hope it will help u

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